PHP日期函数date格式化UNIX时间的方法

本文实例讲述了PHP日期函数date格式化UNIX时间的方法。分享给大家供大家参考。具体分析如下：
日期函数可以根据指定的格式将一个unix时间格式化成想要的文本输出
使用到函数语法如下

string date （string $Format）;string date （string $Format, int $Time）;

下面是演示代码

<?phpecho "When this page was loaded,
";echo "It was then ", date （"r"）, "
";echo "The currend date was ", date （"F j, Y"）, "
";echo "The currend date was ", date （"M j, Y"）, "
";echo "The currend date was ", date （"m/d/y"）, "
";echo "The currend date was the ", date （"jS of M, Y"）, "
";echo "The currend time was ", date （"g:i:s A T"）, "
";echo "The currend time was ", date （"H:i:s O"）, "
";echo date （"Y"）;date （"L"）?（print " is"）:（print " is not"）;echo " a leap year
";echo time （"U"）, " seconds had elapsed since January 1, 1970.
";?>

输出结果如下

It was then Sat, 26 Dec 2009 07:09:51 +0000The currend date was December 26, 2009The currend date was Dec 26, 2009The currend date was 12/26/09The currend date was the 26th of Dec, 2009The currend time was 7:09:51 AM GMTThe currend time was 07:09:51 +00002009 is not a leap year1261811391 seconds had elapsed since January 1, 1970.

希望本文所述对大家的php程序设计有所帮助。