PHP获取一年有几周以及每周开始日期和结束日期

最近接了一个项目，其中有一需求是用php获取一年有几周以及每周开始日期和接触日期。在网上找些资料没有合适的，于是自己做了一份，下面通过两种方式实现PHP获取一年有几周以及每周开始日期和结束日期
代码一：

<?phpheader（"Content-type:text/html;charset=utf-8"）;date_default_timezone_set（"Asia/Shanghai"）;$year = （int）$_GET["year"];$week = （int）$_GET["week"];$weeks = date（"W", mktime（0, 0, 0, 12, 28, $year））;echo $year . "年一共有" . $weeks . "周<br />";if （$week > $weeks || $week <= 0）{ $week = 1;}if （$week < 10）{ $week = "0" . $week;}$timestamp["start"] = strtotime（$year . "W" . $week）;$timestamp["end"] = strtotime（"+1 week -1 day", $timestamp["start"]）;echo $year . "年第" . $week . "周开始时间戳：" . $timestamp["start"] . "<br />";echo $year . "年第" . $week . "周结束时间戳：" . $timestamp["end"] . "<br />";echo $year . "年第" . $week . "周开始日期：" . date（"Y-m-d", $timestamp["start"]） . "<br />";echo $year . "年第" . $week . "周结束日期：" . date（"Y-m-d", $timestamp["end"]）;?>

代码二：

<?phpheader（"Content-type:text/html;charset=utf-8"）;function getIsoWeeksInYear（$year）{ $date = new DateTime; $date->setISODate（$year, 53）; return （$date->format（"W"） === "53" ? 53 : 52）;}function weekday（$custom_date）{ $week_start = date（"d-m-Y", strtotime（"this week monday", $custom_date））; $week_end = date（"d-m-Y", strtotime（"this week sunday", $custom_date））; $week_array[0] = $week_start; $week_array[1] = $week_end; return $week_array;}echo "<br> Weeks in 2013<br>" . getIsoWeeksInYear（2013）;$weekday = weekday（strtotime（date（"d-m-Y", strtotime（"5-8-2013"））））;echo "<br> 10-8-2013";echo "<br>Start: " . $weekday[0];echo "<br>End: " . $weekday[1];?>

以上本文的全部内容，希望对大家学习PHP获取一年有几周以及每周开始日期和结束日期，有所帮助。