首页 / 网页编程 / PHP / PHP响应post请求上传文件的方法

function send_file（$url, $post = "", $file = ""） {$eol = "
";$mime_boundary = md5 （ time （） ）;$data = "";$confirmation = "";date_default_timezone_set （ "Asia/Shanghai" ）;$time = date （ "Y-m-d H:i:s " ）;$post ["filename"] = $file [filename];foreach （ $post as $key => $value ） {$data .= "--" . $mime_boundary . $eol;$data .= "Content-Disposition: form-data; ";$data .= "name=" . $key . $eol . $eol;$data .= $value . $eol;}$data .= "--" . $mime_boundary . $eol;$data .= "Content-Disposition: form-data; name=" . $file [name] . "; filename=" . $file [filename] . $eol;$data .= "Content-Type: text/plain" . $eol;$data .= "Content-Transfer-Encoding: binary" . $eol . $eol;$data .= $file [filedata] . $eol;$data .= "--" . $mime_boundary . "--" . $eol . $eol;$params = array （"http" => array （"method" => "POST", "header" => "Content-Type: multipart/form-data;boundary=" . $mime_boundary . $eol, "content" => $data ） ）;$ctx = stream_context_create （ $params ）;$response = file_get_contents （ $url, FILE_TEXT, $ctx ）;return $response;}