php封装好的人民币数值转中文大写类
class Num2RmbClass{/** * 人民币数值转中文大写 * @author SunsCheung * @time 2015.11.11 * @param string $number 数值 默认为0 * @param string $int_unit 币种单位,默认"元",有的需求可能为"圆" * @param bool $is_round 是否对小数进行四舍五入 * @param bool $is_extra_zero 是否对整数部分以0结尾,小数存在的数字附加0,比如1960.30, * 有的系统要求输出"壹仟玖佰陆拾元零叁角",实际上"壹仟玖佰陆拾元叁角"也是对的 * @param bool $dec_to_int 是否对让小数部分进位到个位,如果进位,个位加1,小数为0, * @return string */public static function num2rmb($number = 0, $int_unit = "元", $is_round = TRUE, $is_extra_zero = FALSE, $dec_to_int = FALSE) {// 将数字切分成两段$parts = explode(".", $number, 2);$int = isset($parts[0]) ? strval($parts[0]) : "0";$dec = isset($parts[1]) ? strval($parts[1]) : "";// 如果小数点后多于2位,不四舍五入就直接截,否则就处理$dec_len = strlen($dec);if (isset($parts[1]) && $dec_len > 2) {if($is_round){if(round(floatval("0.".$dec), 2) == 1 && $dec_to_int){//小数进位到个位$int = empty($int)?1: strval($parts[0]+1);$dec = 0;}elseif(round(floatval("0.".$dec), 2) == 1){//小数不进位到个位$dec = "99";}else{$dec = substr(strrchr(strval(round(floatval("0.".$dec), 2)), "."), 1);echo $dec;die("boss");}}else{$dec = substr($parts[1], 0, 2);}}// 当number为0.001时,小数点后的金额为0元if (empty($int) && empty($dec)) {return "零";}// 定义$chs = array("0","壹","贰","叁","肆","伍","陆","柒","捌","玖");$uni = array("","拾","佰","仟");$dec_uni = array("角", "分");$exp = array("", "万");$res = "";// 整数部分从右向左找for ($i = strlen($int) - 1, $k = 0; $i >= 0; $k++) {$str = "";// 按照中文读写习惯,每4个字为一段进行转化,i一直在减for ($j = 0; $j < 4 && $i >= 0; $j++, $i--) {$u = $int{$i} > 0 ? $uni[$j] : ""; // 非0的数字后面添加单位$str = $chs[$int{$i}] . $u . $str;}//echo $str."|".($k - 2)."<br>";$str = rtrim($str, "0");// 去掉末尾的0$str = preg_replace("/0+/", "零", $str); // 替换多个连续的0if (!isset($exp[$k])) {$exp[$k] = $exp[$k - 2] . "亿"; // 构建单位}$u2 = $str != "" ? $exp[$k] : "";$res = $str . $u2 . $res;}// 如果小数部分处理完之后是00,需要处理下$dec = rtrim($dec, "0");// 小数部分从左向右找if (!empty($dec)) {$res .= $int_unit;// 是否要在整数部分以0结尾的数字后附加0,有的系统有这要求if ($is_extra_zero) {if (substr($int, -1) === "0") {$res.= "零";}}for ($i = 0, $cnt = strlen($dec); $i < $cnt; $i++) {$u = $dec{$i} > 0 ? $dec_uni[$i] : ""; // 非0的数字后面添加单位$res .= $chs[$dec{$i}] . $u;}$res = rtrim($res, "0");// 去掉末尾的0$res = preg_replace("/0+/", "零", $res); // 替换多个连续的0} else {$res .= $int_unit . "整";}return $number < 0 ? "(负)".$res : $res;}}使用方法
//$a = new Num2RmbClass;echo (Num2RmbClass::num2rmb("1600020039.9989","圆",false,false,false));
再给大家分享一个简单点的
function cny($ns) {static $cnums = array("零","壹","贰","叁","肆","伍","陆","柒","捌","玖"), $cnyunits = array("圆","角","分"), $grees = array("拾","佰","仟","万","拾","佰","仟","亿"); list($ns1,$ns2) = explode(".",$ns,2); $ns2 = array_filter(array($ns2[1],$ns2[0])); $ret = array_merge($ns2,array(implode("", _cny_map_unit(str_split($ns1), $grees)), "")); $ret = implode("",array_reverse(_cny_map_unit($ret,$cnyunits))); return str_replace(array_keys($cnums), $cnums,$ret); }function _cny_map_unit($list,$units) { $ul = count($units); $xs = array(); foreach (array_reverse($list) as $x) { $l = count($xs); if($x!="0" || !($l%4)) {$n=($x=="0"?"":$x).($units[($l-1)%$ul]); }else{$n=is_numeric($xs[0][0]) ? $x : ""; }array_unshift($xs, $n); } return $xs; }$value="23058.04";print cny($value);echo"";输出:贰万叁仟零伍拾捌圆肆角再来一个网友做好的也很不错
/***数字金额转换成中文大写金额的函数*String Int $num 要转换的小写数字或小写字符串*return 大写字母*小数位为两位**/function num_to_rmb($num){$c1 = "零壹贰叁肆伍陆柒捌玖";$c2 = "分角元拾佰仟万拾佰仟亿";//精确到分后面就不要了,所以只留两个小数位$num = round($num, 2); //将数字转化为整数$num = $num * 100;if (strlen($num) > 10) {return "金额太大,请检查";} $i = 0;$c = "";while (1) {if ($i == 0) {//获取最后一位数字$n = substr($num, strlen($num)-1, 1);} else {$n = $num % 10;}//每次将最后一位数字转化为中文$p1 = substr($c1, 3 * $n, 3);$p2 = substr($c2, 3 * $i, 3);if ($n != "0" || ($n == "0" && ($p2 == "亿" || $p2 == "万" || $p2 == "元"))) {$c = $p1 . $p2 . $c;} else {$c = $p1 . $c;}$i = $i + 1;//去掉数字最后一位了$num = $num / 10;$num = (int)$num;//结束循环if ($num == 0) {break;} }$j = 0;$slen = strlen($c);while ($j < $slen) {//utf8一个汉字相当3个字符$m = substr($c, $j, 6);//处理数字中很多0的情况,每次循环去掉一个汉字“零”if ($m == "零元" || $m == "零万" || $m == "零亿" || $m == "零零") {$left = substr($c, 0, $j);$right = substr($c, $j + 3);$c = $left . $right;$j = $j-3;$slen = $slen-3;} $j = $j + 3;} //这个是为了去掉类似23.0中最后一个“零”字if (substr($c, strlen($c)-3, 3) == "零") {$c = substr($c, 0, strlen($c)-3);}//将处理的汉字加上“整”if (empty($c)) {return "零元整";}else{return $c . "整";}}echo num_to_rmb(23000000.00); //贰仟叁佰万元整