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首页 / 网页编程 / PHP / PHP获取指定时间段之间的 年,月,天,时,分,秒

核心代码:
Class Utils { /** * format MySQL DateTime (YYYY-MM-DD hh:mm:ss) 把mysql中查找出来的数据格式转换成时间秒数 * @param string $datetime */public function fmDatetime($datetime) {$year = substr($datetime,0,4);$month = substr($datetime,5,2);$day = substr($datetime,8,2);$hour = substr($datetime,11,2);$min = substr($datetime,14,2);$sec = substr($datetime,17,2);return mktime($hour,$min,$sec,$month,$day,0+$year);}/** ** 根据俩个时间获取俩个时间的 包含的 年,月数,天数,小时,分钟,秒 * @param String $start * @param String $end * @return ArrayObject*/ private function diffDateTime($DateStart,$DateEnd){$rs = array();$sYear = substr($DateStart,0,4);$eYear = substr($DateEnd,0,4);$sMonth = substr($DateStart,5,2);$eMonth = substr($DateEnd,5,2);$sDay = substr($DateStart,8,2);$eDay = substr($DateEnd,8,2);$startTime = $this->fmDatetime($DateStart);$endTime = $this->fmDatetime($DateEnd);$dis = $endTime-$startTime;//得到俩个时间的秒数$d = ceil($dis/(24*60*60));//得到天数$rs["day"] = $d;//天数$rs["hour"] = ceil($dis/(60*60));//小时$rs["minute"] = ceil($dis/60);//分钟$rs["second"] = $dis;//秒数$rs["week"] = ceil($d/7);//周$tem = ($eYear-$sYear)*12;//月份$tem1 = $eYear-$sYear;//年if($eMonth-$sMonth<0){//月份相减为负$tem +=($eMonth-$sMonth);}else if($eMonth==$sMonth){//月份相同if($eDay-$sDay>=0){$tem ++;$tem1++;}}else if($eMonth-$sMonth>0){//月份相减正负$tem1++;if($eDay-$sDay>=0){//且日期相减为正数$tem +=($eMonth-$sMonth)+1;}else{$tem +=($eMonth-$sMonth);}}$rs["month"] = $tem;$rs["year"] = $tem1;return $rs;}}
一年多一天,返回的是2年,一个月多一天返回的是2个月,以此推......项目需要,才做此出来,开始我也到网上找这样的例子,但大家都是把年就按365天来算,月就按30天来算,这样算出来的结果肯定是没用的,年有可能是366天,月有可能是31,29,28都有可能