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Android 再按一次后退键退出应用程序
- private static Boolean isExit = false;
- private static Boolean hasTask = false;
- Timer tExit = new Timer();
- TimerTask task = new TimerTask() {
-
- @Override
- public void run() {
- isExit = false;
- hasTask = true;
- }
- };
-
- @Override
- public boolean onKeyDown(int keyCode, KeyEvent event) {
- System.out.println("TabHost_Index.java onKeyDown");
- if (keyCode == KeyEvent.KEYCODE_BACK) {
- if(isExit == false ) {
- isExit = true;
- Toast.makeText(this, "再按一次后退键退出应用程序", Toast.LENGTH_SHORT).show();
- if(!hasTask) {
- tExit.schedule(task, 2000);
- }
- } else {
- finish();
- System.exit(0);
- }
- }
- return false;
- }