Shell脚本中获取SELECT结果值的方法

有时候我们可能会需要在Shell脚本中执行SELECT语句，并将结果赋值给一个变量，对于这样的情形，我们可以用以下的方法来达到目的。#！/bin/ksh
#
# Created : 2015.05.25
# Updated : 2015.05.25
# Author : Jet Chenxi Zhang
# Description : Get SELECT result in Shell# Variable Definitions #
Oracle_SID=audtest
ORACLE_HOME=/app/oracle/product/database/11.2.0/db_1
PATH=$PATH:$ORACLE_HOME/bin
DBNAME=

# Get Database name by quering v$database #
DBNMAE=`
sqlplus -s /nolog <<EOF
set echo off feedback off heading off underline off;
conn / as sysdba;
select name from v\$database;
exit;
EOF`

echo "Database name: "$DBNMAE如上代码，可以将获取Database Name，执行结果如下：[oracle@hxddcx02 ~]$ ./query_dbname.sh
Database name: AUDTEST可以看到SELECT的结果已被正确赋值给Shell的变量。如果SELECT中有多个列的值，也可以用此方法，只是需要将结果进行分拆，如用awk:#！/bin/ksh
#
# Created : 2015.05.25
# Updated : 2015.05.25
# Author : Jet Chenxi Zhang
# Description : Get SELECT results in Shell# Variable Definitions #
ORACLE_SID=audtest
ORACLE_HOME=/app/oracle/product/database/11.2.0/db_1
PATH=$PATH:$ORACLE_HOME/bin
QUERYRES=
DBID=
DBNAME=

# Get Database name by quering v$database #
QUERYRES=`
sqlplus -s /nolog <<EOF
set echo off feedback off heading off underline off;
conn / as sysdba;
select dbid, name from v\$database;
exit;
EOF`

DBID=`echo $QUERYRES | awk -F" " "{print $1}"`
DBNAME=`echo $QUERYRES | awk -F" " "{print $2}"`
echo "Database ID: "$DBID
echo "Database name: "$DBNAME运行结果如下：[oracle@hxddcx02 ~]$ ./query_dbname2.sh
Database ID: 811711272
Database name: AUDTEST本文永久更新链接地址